gcse maths revision

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A simultaneous equation includes two equations and RHS(right hand side) terms and requires you to find the unknowns. For example:

4x + 6y = 12

2x + 5y = 13

are simultaneous equations. The example shows how to solve them.

Solve the simultaneous equations

4x + 6y = 12

and

2x + 5y = 13

To solve simultaneous equations we need to multiply each x or y term by a number that will make one unknown equal in both equations. We then add(or subtract) one equation to the other one. In this case, to make the x's equal, we can multiply the top equation by 1 and the bottom one by 2. This gives:

4x + 6y = 12 (1)

and

4x + 10y = 26. (2)

If we subtract number 1 from number 2 we get :

0x + 4y = 14

y = 14/4 = 3.5.

Now, plugging this value back into any of the 2 equations (I'll go for number 2) gives:

4x + 10 X 3.5 = 26

4x + 35 = 26

4x = - 9

x = - 2.25. We've solved it! (To check, plug the values back into both equations)

In the case of simultaneous equations including fractions, get rid of the fractions and rearrage the equation so it looks like a normal one. Then solve it...........................................

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